Kelly Beatty
OBSERVING BLOG by Kelly Beatty

Space Rock 2009 DD45 Buzzes Earth

Late word out of the IAU's Minor Planet Center: a small asteroid will pass close to Earth tomorrow (March 2nd) at 13:44 Universal Time. How close? The MPC's Timothy Spahr calculates that it'll be 0.00047 astronomical unit from Earth's center. That's only about 40,000 miles (63,500 km) up — well inside the Moon's orbit and roughly twice the altitude of most communications satellites!

This little cosmic surprise, designated 2009 DD45, turned up two days ago as a 19th-magnitude blip in images taken by Rob McNaught at Siding Spring Observatory in Australia. It was already within 1½ million miles of Earth and closing fast.

Thankfully, the news media have become less sensationalistic when it comes to these asteroidal close calls — especially since one actually struck our planet last October 7th, at night, and the impact went virtually unnoticed.

So why post this? Well, we figured someone might want to watch it zip by at up to a half degree per minute! Even though it's small, likely no more than 100 feet (30 meters) across, it'll brighten to magnitude 10½ at its closest — easily within reach of an 8-inch backyard telescope. That's the good news.

The bad news is that the point of closest approach occurs over the Pacific somewhere west of Tahiti, so the most likely viewers are in Australia, Japan, and maybe Hawaii. Sure, you could look before or afterward, but it'll be brighter than 13th magnitude only for a few hours.

If you want to give it a try anyway, you'll need to generate an ephemeris of positions for your specific location, due to the wide parallax of an object so close to Earth. And if you manage to spot it, be sure to add a comment below to let us know.

By the way, this isn't the closest "near-miss" asteroidal fragment on record. According to the MPC, tiny 2004 FU162 skirted just 4,000 miles from us on March 31, 2004.

Posted by Kelly Beatty, March 1, 2009
related content: Solar system
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Stellarium information

Posted by Mark Smith March 1, 2009 At 05:04 PM PST
if you have a reference on how to view this in stellarium it would give me a great way of discovering it.


Stellarium 0.9.x update

Posted by Blake March 1, 2009 At 05:31 PM PST
Stellarium does not have this built in. You'll need to add the following to your SSYSTEM.INI file. [2009 DD45] # updated on 20:23 01/03/2009 # data from JPL SSD http://ssd.jpl.nasa.gov/ name = asteroid (2009 DD45) parent = Sun radius = 1 oblateness = 0.0 halo = true color = 1.0,1.0,1.0 tex_halo = star16x16.png tex_map = nomap.png coord_func = comet_orbit orbit_Epoch = 2454800.5 orbit_MeanAnomaly = 299.315874067907 orbit_SemiMajorAxis = 1.346947583166917 orbit_Eccentricity = 0.2642230845965119 orbit_ArgOfPericenter = 4.051609765200548 orbit_AscendingNode = 162.0802983813538 orbit_Inclination = 13.17107278860191 sidereal_period = 570.9846984060146 lighting = true albedo = 1 This information is specifically for Stellarium 0.9.x. If you're using the newer 0.10.x version, you need to change the parameter sidereal_period for orbit_visualization_period. You've not indicated your version or platform so I cannot give more details.. If you need more assistance working with Stellarium, you should put further questions to the their forum. I just added it. It's a fast mover! cheers, Blake


widefield imaging RT capture

Posted by Mike March 4, 2009 At 11:43 PM PST
This incredible widefield image of 2009 dd45 at it's nearest approach from Canberra http://www.youtube.com/watch?v=_RKKgMDK7A4


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